find the smallest number which when divided by 28 and 32 leaving remainder 8 and 12 respectively.
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Heya friend...
Here is your answer...
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Remainder : 28 -> 8 = 20
: 32 -> 12 = 20
The no. that must divide them equally is nothing but 20, because 10 will not give the given remainder...
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hope this helps you...
Jeferson
Here is your answer...
______________________________________________________________
Remainder : 28 -> 8 = 20
: 32 -> 12 = 20
The no. that must divide them equally is nothing but 20, because 10 will not give the given remainder...
______________________________________________________________
hope this helps you...
Jeferson
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answer is 204
friend if you know the answer, then why did you ask the question?
the answer is given on book
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