Find the smallest number which when divided by 3 5 and 7 leaves
Answers
Answer:
35 is the smallest number which when divided by 3 5 and 7
Step-by-step explanation:
35/35=1
35/7 =5
Answer:
737
Step-by-step explanation:
According to question,
The smallest no divisible by 5,3 and 7 and leaving reminder 2 and also divisible by 11
The smallest number divisible by 5 , 3 , 7 = LCM ( 5 , 3 , 7 )
LCM of 5 , 3 , 7 = 5 * 3 * 7
= 105
In each of the case remainder is 2
So,
The desired number = 105 + 2 = 107
But 107 is not divisible by 11
Therefore,
The number which when divided by 3, 5 and 7 leaves a remainder 2 and also is divisible by 11 is 737
As,
To be divisible by 11, it is necessary that difference between the digit's sum at odd places and digit's sum at even place is 0 or divisible by 11.
Here 737 = 7 + 7 - 3 = 11, which is divisible by 11
Also,
737 / 3 leaves remainder 2
737 / 5 also leaves remainder 2
737 / 7 also leaves remainder 2
Hence,
Answer is 737