Math, asked by shubhkohli, 1 year ago

find the smallest number which when divided by 30 32 48 and 24 leaves a remainder 5 in each case

Answers

Answered by mlw43556
2
Find the LCM of the given numbers
Add the given remainder to the calculated LCM

Solution of the asked question :

LCM of 24 , 32 & 42 = 672

The least possible number for your given case = 672 +5 = 677


riya1000: I am sorry but I think you forgot 30?
riya1000: amd made 48, 42
mlw43556: i did
shubhkohli: yes
riya1000: so is it right or am I wrong?
shubhkohli: 30, 32,48,24
shubhkohli: actually i too don't know
riya1000: mark as brainliest please
shubhkohli: ok
Answered by riya1000
9
The LCM of these numbers is 480, in order to find a number such, just add 5 to the number...answer is 485.
Please correct me if I am wrong...if I am right mark as brainliest please
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