Find the smallest number which when divided by 30,40,60 leaves the same remainder 7 in each case
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Least common multiple of 30, 40 and 60 is 120, which means that 120 is the smallest number which when divided by 30, 40 and 60 leaves 0 as the remainder. Thus, If we add 7 to 120 we will get 127 which when divided by 30, 40 and 60 leaves remainder 7.
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Answer:
lCM = 120
add 7 to LCM
=127 which cannot be divided by any and give remainder 7
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