Question

find the smallest
number which
when divided
by 30, 40, 60 leaves
the
remainder in
in each cases​

Answer 1

Answer:

127

Step-by-step explanation:

Least common multiple of 30, 40 and 60 is 120, which means that 120 is the smallest number which when divided by 30, 40 and 60 leaves 0 as the remainder.

Thus, If we add 7 to 120 we will get 127 which when divided by 30, 40 and 60 leaves remainder 7.

Answer 2

Answer:

127

Step-by-step explanation:

You've to take the LCM ( and why LCM? because you've to find the dividend as 'divided by' is mentioned over there)

Before taking the LCM , you need to find the factors of the three numbers.

30= 2*3*5

40= 2*2*2*5

60=2*2*3*5

LCM= 2*2*2*3*5= 120

And the number when divided by 30,40 and 60 leaves the reminder 7 , so the number must be 127.

Thank You.