Find the smallest number which when divided by 30, 40 and 50leaves the remainder 5 in each case.
Answers
Answered by
0
Answer:
answer is 125
Step-by-step explanation:
50 divided by 125 leaves remainder 5
same with every number because lcm of 30 , 40, 50 is 120 hence it is divisible we add the required remainder to it
required remainder is 5 then 120 + 5 = 125 //
Similar questions