Math, asked by Anshugour, 1 year ago

find the smallest number which when divided by 30 , 40 and 60 leaves the remainder 7 in each case

Answers

Answered by Aman2630
91

Answer:

127

Step-by-step explanation:

Least common multiple of 30, 40 and 60 is 120, which means that 120 is the smallest number which when divided by 30, 40 and 60 leaves 0 as the remainder.

Thus, If we add 7 to 120 we will get 127 which when divided by 30, 40 and 60 leaves remainder 7.

Answered by nehamalhotra21
20

Answer:

Here is your answer.

Hope it will be helpful.

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