find the smallest number which when divided by 30 , 40 and 60 leaves the remainder 7 in each case
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Answered by
91
Answer:
127
Step-by-step explanation:
Least common multiple of 30, 40 and 60 is 120, which means that 120 is the smallest number which when divided by 30, 40 and 60 leaves 0 as the remainder.
Thus, If we add 7 to 120 we will get 127 which when divided by 30, 40 and 60 leaves remainder 7.
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