Math, asked by bhuraramchoudhary035, 9 months ago

Find the smallest number which when divided by 30,40 and 60 leaves the remainder 7 in each case ​

Answers

Answered by tishaahuja2004
1

Answer:30-7=23

40-7=33

60-7=53

LCM of 23,33,53=23*33*53=

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Answered by 16RE78
3

Answer:

Answer:30-7=23

40-7=33

60-7=53

LCM of 23,33,53=23*33*53= 40227.

if this is correct pls mark me as brainlest. thanks.

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