Question

find the smallest number which when divided by 30,40,and 60 leaves the remainder 7in each case​

Answer 1

Here is your answer:

To find,

The smallest number when divided by 30, 40 & 60. leaving the same remainder 7 in each case.

Solution:

Now let us find the LCM of these three numbers.

⇒ 30 = 2 × 3 × 5

⇒ 40 = 2³ × 5

⇒ 60 = 2² × 3 × 5.

The LCM = 2³ × 3 × 5 = 120.

Then, 120 is the number which is exactly divisible. 

Then, 120 + 7 = 127. This number leaves remainder 7 when divided by those 3 number.

Hence 127 is the smallest number that leaves 7 as remainder which divided by those numbers.

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