Math, asked by sidhuamritpalsidhu00, 1 month ago

find the smallest number which when divided by 30,40and 60leaves the remainder 7un each case​

Answers

Answered by avisaxena0209
0

Answer:

I thin it is 2700

ok so pls mark me brainliest

Answered by simranraju09
0

Answer:

127

Step-by-step explanation:

Answer. Step-by-step explanation: Least common multiple of 30, 40 and 60 is 120, which means that 120 is the smallest number which when divided by 30, 40 and 60 leaves 0 as the remainder. Thus, If we add 7 to 120 we will get 127 which when divided by 30, 40 and 60 leaves remainder 7.08.

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