find the smallest number which when divided by 30 and 45 leaves5as remainder in the cases
Answers
Answered by
0
let the smallest no. be x
x/30=5
so x=30*5=150
and x/45=5
so x=45*5=225
x/30=5
so x=30*5=150
and x/45=5
so x=45*5=225
Similar questions