Math, asked by swaroopsunil8618, 9 months ago

Find the smallest number which when divided by 32, 72 and 80 leaves remainder 14 in each case

Answers

Answered by archan4

0

Answer:

1454

Step-by-step explanation:

L. C. M of 32,72,80= 2×2×2×2×2×9×5

= 1440

It leaves remainder 14 in each case

then 1440+14 = 1454

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