Question

Find the smallest number which when divided by 35 36 72 and80leaves aremainder1 in each case

Answer 1

Answer:

The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)

35=5×7

56=2

3

×7

91=7×13

LCM=2

3

×5×7×13=3640

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.