Question

find the smallest number which when divided by 35,56,105 leave a remainder 6 in each case



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Answer 1

Answer:

Step-by-step explanation:

here, we must first subtract 6 from each of the numbers.

(35 - 6 = 31), (56 - 6 = 50), (105 - 6 = 99)

here, "smallest number" denotes that we have to find HCF, and the HCF of the numbers using long division method is 7. (see attachment below for explaination of it)