find the smallest number which when divided by 35,56,91 leaves the same remainder 7 in each case
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For leaving remainder 7 we will minus 7 from all no.
35
-7=28
56
-7=49
91
-7=86
Now,it had told to find the smalles no. so we will do the L.C.M of 28,49,86=8428
So,the smallest no.is=8428ans
35
-7=28
56
-7=49
91
-7=86
Now,it had told to find the smalles no. so we will do the L.C.M of 28,49,86=8428
So,the smallest no.is=8428ans
shadowsabers03:
Wrong answer 8428 is.
A mistake in the solution:- 91 - 7 = 84, not 86.
The answer is so simple! The answer is 3647. Take the LCM of the divisors required (i. e., 35, 56, 91) and add the remainder 7.
oups sorry
It's OK.
Next time, read the question carefully, try to find the solution, and publish the answer.
all right
i think it is not right answerr
Which is not?
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