Question

find the smallest number which when divided by 35,86,72 and 80 and leaves a remainder 1 in each case.​

Answer 1

Step-by-step explanation:

Solution

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Correct option is

A

3647

The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)

35=5×7

56=2

3

×7

91=7×13

LCM=2

3

×5×7×13=3640

The smallest number that when divided by 35, 56

Answer 2

Answer:

500401 is the answer

Step-by-step explanation:

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