Math, asked by Sonwani4612, 21 days ago

Find the smallest number which when divided by 39 52 165 leaves a remainder of 5 in each case

Answers

Answered by pranav17087

Answer:

L.C.M. of 39, 52 and 65. So, the smallest number is 785, which when divided by 39, 52 and 65 leaves a remainder of 5 in each case.

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