Math, asked by sakchi2, 1 year ago

Find the smallest number which when divided by 39,52 and 65 , leaves a remainder of 5 in each case

Answers

Answered by niteshkum123
3
LCM of 39,52,65 = 13*3*4*5 = 780
The smallest no leaving remainder 5 is= 
LCM of the no.s - the required remainder

= 780-5 = 775
hope it helps 
mark as brainliest plz if u like. :)

sakchi2: sorry but your answer is wrong it's 785
sakchi2: but u have tried your best
niteshkum123: hmm
sakchi2: I have marked u brainly
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