Math, asked by rp87339, 2 months ago

find the smallest number which when divided by 39,52and 65 leaves a remainder of 5 in each case.

Answers

Answered by navyamanikandan

0

Answer:

785

So, the smallest number is 785, which when divided by 39, 52 and 65 leaves a remainder of 5 in each case.

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