Math, asked by atharvathakre34, 6 months ago

Find the smallest number which when divided by 40 60 and 100 leaves 24 as the remainder in each case.

Answers

Answered by 170320106072clrutvap

2

Answer:

624

Step-by-step explanation:

first find the LCM of 40,60,100 = 20 x 2 x 3 x 5 = 600

Now add the remainder to their LCM = 600+24= 624

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