Math, asked by Anonymous, 5 hours ago

Find the smallest number which when divided by 42 and 54 leaves the remainders 34 and
46 respectively.


chapter \: name \:  =  \: hcf \: and \: lcm

Answers

Answered by devkumarip9
8

Step-by-step explanation:

First, we need to fond the LCM of 42 and 54. The LCM of 42 and 54 is 378.

Now, we shall find the difference of 42 and 34 which is 8. Similarly, the difference of 54 and 46 is also 8.

The difference of the LCM and 8 is the smallest number.

So, 378−8=370.

Hence, 370 is the smallest number when divided by 42 and 54 leave remainders 34 and 46 respectively

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Answered by kv44489
2

Answer:

LCM of 42 and 54 is 378

and HCF of 42 and 54 is 8

LCM - HCF = 378-8 = 370

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