Question

Find the smallest number which when divided by 45 and 60 leaves 7 as the remainder in each case ​

Answer 1

ans is (1) 187

187-7=180

45×4 =180

60×3=180

Answer 2

Answer:

The number which when divided by 45 and 60 leaves 7 as the remainder in each case ​is 187.

Step-by-step explanation:

Let the number be x

Now we need to find a number which is divisible by both 45 and 60:

LCM:

45 = 3 × 3 × 5

60 = 2 × 2 × 3 × 5

LCM = 2 × 2 × 3 × 3 × 5

LCM = 180

Now, since the remainder in each case is 7, we need to add 7 to the LCM:

x = 180 + 7 = 187.

Therefore, the number which when divided by 45 and 60 leaves 7 as the remainder in each case ​is 187.

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