Find the smallest number which when divided by 45 and 63 leaves remainder 8 and 12 respectively
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45-8= 37.
63-12=51.
LCM of 37 and 51 :
37= 1*37
51=3*17
LCM of 37 and 51 =37*3*17=1887.
Hence,the smallest number which when divided by 45 and 63 leaves remainder 8 and 12 is 1887.
HOPE IT HELPS U..
63-12=51.
LCM of 37 and 51 :
37= 1*37
51=3*17
LCM of 37 and 51 =37*3*17=1887.
Hence,the smallest number which when divided by 45 and 63 leaves remainder 8 and 12 is 1887.
HOPE IT HELPS U..
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