Question

Find the smallest number which when divided by 45 and 63 leaves remainder 8 and 12 respectively

Answer 1

45-8= 37.

63-12=51.

LCM of 37 and 51 :

37= 1*37

51=3*17

LCM of 37 and 51 =37*3*17=1887.

Hence,the smallest number which when divided by 45 and 63 leaves remainder 8 and 12 is 1887.

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