Math, asked by nishashaw, 1 year ago

find the smallest number which when divided by 5 become TV 1242 and 56 and 17

Answers

Answered by aski
0
For this particular sum we need to find the LCM of the given numbers.

The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 91

35 = 5 x 7
56 = 2 x 2 x 2 x 7
91 = 7 x 13

LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640

The smallest number which divides 35,56 and 91 is 3640. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (3640+7=3647).

Hence the smallest number that when divided by 35,56,91 leaves a remainder 7 is 3647.

Answered by wwefanclub078
0

For this particular sum we need to find the LCM of the given numbers.

The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 91

35 = 5 x 7
56 = 2 x 2 x 2 x 7
91 = 7 x 13

LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640

The smallest number which divides 35,56 and 91 is 3640. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (3640+7=3647).

Hence the smallest number that when divided by 35,56,91 leaves a remainder 7 is 3647.

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