find the smallest number which when divided by 55 66 and 88 leaves 2 as reminder
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it is right answer I hope you get your answer
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Answer:
find LCM of the numbers.
66=2*3*11.
88=2*2*2*11.
77=7*11
LCM=2*2*2*3*7*11=924
As it has to leave a remainder 3 when divided by these numbers the required number is 924+6=930
930 is the required number.
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