Math, asked by devidivya746, 5 months ago

Find the smallest number which when divided by 55 and 121 leaves the remainder 16 in each case.

Answers

Answered by sinhakriti1711

3

Answer:

lcm of 55 and 121 = 605

req. no. = 605 +16 = 621

Step-by-step explanation:

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Answered by seemaprajapati614

0

Answer:

the no. divided by 55 is 880 and

the no. divided by 121 is 1936

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