Question

Find the smallest number which when divided by 57,76 and 190 .Leaves the remainder 10 in case

Answer 1

The required number is 1150.

Step-by-step explanation:

Consider the provided information.

We need to find the smallest number which when divided by 57,76 and 190 . Leaves the remainder 10 in case.

First find the LCM of 57, 76 and 190.

57 = 3 × 19

76 = 2 × 2 × 19

190 = 2 × 5 × 19

The LCM is: 2 × 2 × 3 × 5 × 19 = 1140

That means the least number which is completely divisible by 57, 76 and 190 is 1140.

But we want remainder should be 10.

So, add 10 in 1140.

1140+10=1150

Hence, the smallest number which when divided by 57,76 and 190 leaves the remainder 10 in case is 1150.

#Learn more

Find LCM of 92 and 510.Also find their HCF by using LCM.

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