Question

Find the smallest number which, when
divided by 6, 15, and 18, leaves the
remainder 5 in each case.​

Answer 1

Answer:

its 5

Step-by-step explanation:

and 6 i don't know sorry

Answer 2

Answer is 95

Explanation :-

We have to take LCM of 6, 15 and 18

6 = 2 × 3

15 = 3 × 5

18 = 2 × 3 × 3

LCM = 2 × 3 × 3 × 5 = 90

So, For leaving remainder 5, = 90 + 5 = 95

Hence, 95 is the required number

Hope it helps u