Math, asked by asnasaba1234, 19 days ago

Find the smallest number which when divided by 6, 15 and 21 leaves remainder.

Answers

Answered by sohampanhale

1

Answer:

12 bdhds you gonna bonna Marine clarify magic

Answered by XxDashingPrincexX

2

Answer:

209

Step-by-step explanation:

First find the LCM of 6,15,21 since they said the smallest number

The LCM is then 210.

Get 210-1

=209.

So 209 leaves a remainder of 1 in each case.

Hope it helps

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