find the smallest number which when divided by 6 7 or 8 will leave remainder 5 in each case.
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Answered by
7
Answer:
Prime factorization of 6 = 2 * 3
Prime factorization of 7 = 7
Prime factorization of 8 = 2 * 2 * 2
LCM(6,7,8) = 168.
The smallest number that when divided by 6,7,8 will leave remainder 5 in each case = 168 + 5 = 173.
Therefore the smallest number = 173.
Explanation:
Answered by
1
Answer:
Ans is (B) 173 Thank you.
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