Find the smallest number which when divided by 6 8 12 15 20 leaves same remainder 5
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Answer: L.C.M of 6=6=2×3
L.C.M of 8= 2×2×2
L.C.M of 12= 2×2×3
L.C.M of 15= 5×3
L.C.M of 20= 2×2×5
L.C.M of 6, 8, 12, 15, 20 =2×2×2×3×5
=120.
120 is the smallest number which will completely divide the numbers (6, 8, 12, 15, 20).
Since, we want remainder 5.
Therefore, the required smallest number is 120+5=125
Note:
The below mentioned points will help you to solve this kind of questions:
1) Whenever you are required to find a number that is divisible by more than one number, find LCM.
2) Whenever you are required to find a number that completely divides more than one number, find HCF.
Step-by-step explanation:
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0
Step-by-step explanation:
the desired ans cam be obtained by taking the LCM and subtracting 5 from the LCM
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