Find the smallest number which when divided by 6,8,12,15, and 20 leaves the same remainder 5
Answers
Answered by
0
Answer:
125
Step-by-step explanation:
Find the LCM of all numbers
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Answered by
0
Answer:
125
Step-by-step explanation:
lcm of 6,8,12,15 = 120
120 ->smallest no divisible by 6,8,12 and 15
so, 120+5 will leave a remainder 5 for all these numbers
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