Find the smallest number which when divided by 6, 8, 12, 15 and 20 leaves the same
remainder 5.
Answers
Answered by
0
Answer:
65
Step-by-step explanation:
Answered by
2
Answer:
125
Step-by-step explanation:
L.C.M of 6, 8, 12, 15, 20 =2×2×2×3×5
=120.
120 is the smallest number which will completely divide the numbers (6, 8, 12, 15, 20). Since, we want remainder 5.
Therefore, the required smallest number is 120+5=125
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