Math, asked by tarikmohd435, 1 month ago

find the smallest number which when divided by 66, 77 and 88 leaves 2 as remainder.

Answers

Answered by mukesh9935328684

0

Answer:

3698

Step-by-step explanation:

LCM of 66 , 77 , 88 is 3696

Required No. LCM + Remainder

3696 + 2 = 3698

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