Math, asked by tarikmohd435, 25 days ago

find the smallest number which when divided by 66, 77 and 88 leaves 2 as remainder.

Answers

Answered by sasnayakbbsr

0

Answer:

Let us find LCM of the numbers. 66=2*3*11. 88=2*2*2*11. 930 is the required number.

Step-by-step explanation:

hope it helps

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