Find the smallest number which when divided by 7 or 15 leaves a remainder 2 in each case.
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The lcm of7, 15 is 105
So we add the reminder 105+2=
107
On dividing 107÷7
Reminder =2
On dividing 107÷15
Reminder =2
So the number is 107
So we add the reminder 105+2=
107
On dividing 107÷7
Reminder =2
On dividing 107÷15
Reminder =2
So the number is 107
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