Math, asked by sraut7505, 12 hours ago

find the smallest number which when divided by 8,10,12,15, gives a remaindar of 5 every time​

Answers

Answered by 89kashishchauhan79
0

Answer:

365 is the smallest number which when divided by 8, 9, 10, 15, 20 gives a remainder of 5 everytime.

Answered by manisha7812
0

Answer:

this is your answer

Step-by-step explanation:

Hence, 365 is the smallest number which when divided by 8, 9, 10, 15, 20 gives a remainder of 5 every time.

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