Find the smallest number which when divided by 8 10 and 12 gives a Remainder of 4 every time
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The LCM of 8, 10, and 12 is 120.
120 . . . . ; multiples of 10 = 10, 20, 30, 40 . . . . 120 . . . . ; multiples of 12 = 12, 24, 36, 48 . . . . 120 . . . . ) and choose the smallest multiple that is exactly divisible by 8, 10, and 12, i.e., 120.
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take the LCM of given numbers
LCM of 8,10,12=120
let the number be x
given that when x is divided by 8 10 and 12 gives a Remainder of 4 every time
so x must be 4 more than the least common multiple of the numbers
x=120+4
=124
therefore the smallest number which when divided by 8 10 and 12 gives a Remainder of 4 every time is 124
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