find the smallest number which when divided by 8, 12 ,16, 24 and 36 leaves no remainder
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Answered by
11
divide by 4 if we divide four no remainder will left try it
arpan33:
what answer will vom
Answered by
15
First we have to find the L.C.M of 12,16,24,36
L.C.M by prime factorization method
8=2*2*2
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
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Hope this will help you......
L.C.M by prime factorization method
8=2*2*2
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
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Hope this will help you......
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