Math, asked by arpan33, 1 year ago

find the smallest number which when divided by 8, 12 ,16, 24 and 36 leaves no remainder

Answers

Answered by sanskaryt
11
divide by 4 if we divide four no remainder will left try it

arpan33: what answer will vom
arpan33: come#
Answered by Shubhendu8898
15
First we have to find the L.C.M of 12,16,24,36

L.C.M by prime factorization method
8=2*2*2
12= 2*2*3

16=2*2*2*2

24= 2*2*2*3

36= 2*2*3*3

L.C.M= 2*2*2*2*3*3 = 144


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Hope this will help you......

arpan33: what's the answer and were to put 8
Shubhendu8898: now it is corrected
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