Question

find the smallest number which when divided by 8,12,20, or 25 leaves a remainder 5 in each case​

Answer 1

acc to question

Answer:

lcm of 8.12.20.15=600

now,we add 5 to lcm=5+600=605

number is 605

Answer 2

Answer:

Required smallest number is 605.

Step-by-step explanation:

Given four numbers are 8,12,20,25 and It is also given the smallest number which when divided by 8,12,20, or 25 leaves a remainder 5.

Here we want to find the smallest number.

If we find LCM of 8,12,20,25 and the LCM add with 5 then we can find the required smallest number.

LCM means Lowest Common Multiple.

By prime factorisation,

$8 = 2 \times 2 \times 2 \\ 12 = 2 \times 2 \times 3 \\ 20 = 2 \times 2 \times 5 \\ 25 = 5 \times 5$

So, lowest common multiple of 8,12,20,25 is (5×5×2×2×2×3) = 600

Therefore LCM of 8,12,20,25 is 600.

and required smallest number is (600+5) = 605.

Know more about LCM,

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