Question

Find the smallest number, which when divided by 8, 12, 20 or 25 leaves a remainder
5 in each case?
(A)595
(B) 605
(C) 1205
(D)1195 ​

Answer 1

Answer:

595 are the smallest number, which when divided by 9,12,20 or 25 leaves a remainder 5 in each case.

Answer 2

The correct answer is option (B) 605

GIVEN

Divisor- 8, 12, 20, 25

TO FIND

The smallest number when divided by the given numbers leaves 5 as a remainder.

SOLUTION

We can simply solve the above problem as follows-

To find the lowest possible number, we will first calculate the LCM of 8, 12, 20, and 25.

LCM OF 8, 12, 20, and 25. -

2 | 8 12 20 25

2 | 4 6 10 25

2 | 2 3 5 25

3 |1 3 5 25

5 | 1 1 5 25

5 |1 1 1 5

1 |1. 1. 1. 1

LCM = 2×2×2×3 ×5×5 = 600

So, 600 is the smallest number which will be exactly divided by 8, 12, 20 and 25

But we have to find the number which will leave 5 as a remainder.

The smallest number will be 600+5 = 605.

Hence, the smallest number when divided by 8, 12, 20, and 25 will leave a remainder of 5 is 605.

#spj2

For more questions-

https://brainly.in/question/35994378?utm_source=android&utm_medium=share&utm_campaign=question

https://brainly.in/question/47857182?utm_source=android&utm_medium=share&utm_campaign=question