Question

Find the smallest number which when
divided by 8, 12 and 15 leaves a
remainder of 2 in each case​

Answer 1

Answer:

3 is the answer.............

Answer 2

Answer:

lcm of 8,12,15

8=2×2×2

12=2×2×3

15=5×3

lcm=2×2×3×2×5

lcm=120

so the number is 120+2=122