find the smallest number which when divided by 8 12 and 15
leave no remainder
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Answer:
Remainder are also the required number 8 & 12. Hence 204 is the required answer.
Explanation:
The least number which is exactly divisible by each given number is their L.C.M.
Required number L.C.M. of 12, 15, 18, 24, and 36.
∴ L.C.M. = least required number
=2×2×3×3×5×2=360
Hence, the least required number = 360
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