Question

Find the smallest number which when divided by 8,9,10,15,20 gives the remainder 5 every time

Answer 1

Good night mate


here is your answer

Answer 2

Answer:

365 is the smallest number which divided by given number and leave 5 as remainder in all case.

Step-by-step explanation:

Given Numbers are 8 , 9 , 10 , 15 , 20

We need to find the smallest number which divided by given number and leave 5 as remainder in all case.

We find LCM of the given numbers.

As LCM is the smallest number which is exactly divisible by given numbers.

By prime factorization method,

8 = 2 × 2 × 2

9 = 3 × 3

10 = 2 × 5

15 = 3 × 5

20 = 2 × 2 × 5

LCM = 2 × 5 × 2 × 3 × 2 × 3 = 360

Thus, Required number = 360 + 5 = 365

Therefore, 365 is the smallest number which divided by given number and leave 5 as remainder in all case.