Question

Find the smallest number, which when divided by 80 and 64 leaves no remainder.​

Answer 1

Answer:

Step-by-step explanation:

To find the smallest number which when divide by 80 and 64 leaves no reminder

we must find the LCM of the given two numbers.

which is:

(by prime factorizaton)

80 = 2*2*2*2*5

64= 2*2*2*2*2*2

So.LCM of 64,80 is 2*2*2*2*2*2*5 = 320

hope it helps you ☺️