Math, asked by hkjaggesha, 1 year ago

find the smallest number which when divided by 9, 12, 15, 18 leaves a remainder of 5 each case

Answers

Answered by samia15
7

LCM of 9,12,15,18=185

hence when the no. 185 is devided by 9,12,15,18 it leaves behind the reminder 5.

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Answered by VaibhavSR
0

Answer: 185

Step-by-step explanation:

To find:- The smallest number which when divided by 9, 12, 15, 18 and leaves remainder of 5 in each case.

Concept:- The Lowest common multiple of the given number will be added by 5 to give the required number.

Solution:-

The LCM of 9, 12, 15 and 18 is 180.

∴ Required number= 180+5

                              = 185

  • Hence, the required number is 185.

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