Math, asked by kevy4428, 7 months ago

Find the smallest number which when divided by t 39, 52,and 65, leaves a remainder of 5 in each case

Answers

Answered by mdp1175
1

Answer:

785

Step-by-step explanation:

39= 13*3

52= 2*2*13

65= 13*5

L.C.M (39,52,65)= 2² * 3 * 5 * 13

L.C.M (39,52,65)= 20*39

L.C.M. (39,52,65)= 780

780+5 = 785

Therefore, 785 is the smallest number which when divided by 39,52 and 65, leaves a remainder of 5 in each case.

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