Find the smallest number which when divided by t 39, 52,and 65, leaves a remainder of 5 in each case
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Answer:
785
Step-by-step explanation:
39= 13*3
52= 2*2*13
65= 13*5
L.C.M (39,52,65)= 2² * 3 * 5 * 13
L.C.M (39,52,65)= 20*39
L.C.M. (39,52,65)= 780
780+5 = 785
Therefore, 785 is the smallest number which when divided by 39,52 and 65, leaves a remainder of 5 in each case.
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