find the smallest number which when divided separately by 12, 20 and 24 leaves 7 as remainder
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Answered by
2
12 = 2*2*3
20 = 2*2*5
24= 2*2*3
LCM = 3*3*5 => 45
The number we want 45 + 7 = 52
20 = 2*2*5
24= 2*2*3
LCM = 3*3*5 => 45
The number we want 45 + 7 = 52
Answered by
5
Answer:
The smallest number is LCM of (12,20and 24) +7=127
ok
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