Math, asked by arsh0604, 1 year ago

find the smallest number which when divided separately by 12, 20 and 24 leaves 7 as remainder​

Answers

Answered by manarth
2
12 = 2*2*3
20 = 2*2*5
24= 2*2*3

LCM = 3*3*5 => 45

The number we want 45 + 7 = 52
Answered by ghanshyamkumar51
5

Answer:

The smallest number is LCM of (12,20and 24) +7=127

ok

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