Math, asked by copyright5, 3 months ago

find the smallest number which when divides by 5, 7, and 9 gives 1 as remainder.

Answers

Answered by ddviarti

0

Answer:

Step-by-step explanation:

The required numbers to divide is (5-1)=4 ,(7-1)=6 and (9-1)=8.

HCF(4,6,8)=2

Hence the smallest number is 2.

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