find the smallest number which when increase by 17 is exactly divisible by 520 and 468
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Answered by
6
Firstly divide the 520 and 468 info simplest then add 17into it . Then u get the ans
10simran:
glat aa raha h answer
see my answer it is right
no
I think it's right
Answered by
18
Let us find LCM of 520 & 468
520=2×260
=2×2×130
=2×2×2×65
=2×2×2×5×13
468=2×234
=2×2×117
=2×2×3×3×13
LCM=2×2×2×3×3×5×13
=468×9
=4212
so the smallest number =4212-17=4195
520=2×260
=2×2×130
=2×2×2×65
=2×2×2×5×13
468=2×234
=2×2×117
=2×2×3×3×13
LCM=2×2×2×3×3×5×13
=468×9
=4212
so the smallest number =4212-17=4195
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